Method TakeEvery
| Edit this pageTakeEvery<TSource>(IEnumerable<TSource>, int)
Returns every N-th element of a sequence.
Declaration
public static IEnumerable<TSource> TakeEvery<TSource>(this IEnumerable<TSource> source, int step)Parameters
| Type | Name | Description |
|---|---|---|
| IEnumerable<TSource> | source | Source sequence |
| int | step | Number of elements to bypass before returning the next element. |
Returns
| Type | Description |
|---|---|
| IEnumerable<TSource> | A sequence with every N-th element of the input sequence. |
Type Parameters
| Name | Description |
|---|---|
| TSource | Type of the source sequence |
Remarks
This operator uses deferred execution and streams its results.
Examples
The following code example demonstrates how to take every n-th element of a sequence using TakeEvery.
var sequence = Enumerable.Range(1, 6);
// Take every 2nd element of the sequence
var result = sequence
.TakeEvery(2);
Console.WriteLine(
"[" +
string.Join(", ", result) +
"]");
// This code produces the following output:
// [1, 3, 5]
Exceptions
| Type | Condition |
|---|---|
| ArgumentNullException |
|
| ArgumentOutOfRangeException |
|